# Differentiator MCQ’s

This set of Linear Integrated Circuits Multiple Choice Questions & Answers (MCQs) focuses on “Differentiator”.

1. Find out the differentiator circuit from the given circuits?
a)

b)

c)

d)

2. Determine the output voltage of the differentiator?
a) VO = RF×C1×[dVin/dt].
b) VO = -RF×C1×[dVin/dt].
c) VO = RF×CF×[dVin/dt].
d) None of the mentioned

3. Differentiation amplifier produces
a) Output waveform as integration of input waveform
b) Input waveform as integration of output waveform
c) Output waveform as derivative of input waveform
d) Input waveform as derivative of output waveform

4. which factor makes the differentiator circuit unstable?
a) Output impedance
b) Input voltage
c) Noise
d) Gain

5. Calculate the gain limiting frequency for the circuit

a) 15.64Hz
b) 23.356Hz
c) 33.89Hz
d) None of the mentioned

6. Select the order in which the frequency should be maintained to enhance the stability of differentiator? Where fa -> Frequency at which gain =0 ; fb -> Gain limit frequency ; fc -> Unity gain bandwidth.
a) fa < fb < fc
b) fa > fb > fc
c) fb < fc > fa
d) fb < fc < fa

7. The increase in the input frequency of the differentiation amplifier to input impedance creates
a) Component noise
b) External noise
c) Low frequency noise
d) High frequency noise

8. The stability and high frequency noise problem are corrected by
b) Feedback capacitor and internal resistor
c) Feedback capacitor and feedback resistor
d) Internal capacitor and internal capacitor

9. Which application use differentiator circuit?
a) None of the mentioned
b) FM modulators
c) Wave generators
d) Frequency Shift keying

10. Choose the value of RF and C for a 5kHz input signal to obtain good differentiation.
a) RF = 1.6×103Ω, C1 = 33×10-6F
b) RF = 1.6×103Ω, C1 = 0.47×10-6F
c) RF = 1.6×103Ω, C1 = 47×10-6F
d) RF = 1.6×103 Ω, C1 = 10×10-6F

11. A sine wave of 1vpeak at 1000Hz is applied to a differentiator with the following specification: RF =1kΩ and C1=0.33µF, find the output waveform?
a)

b)

c)

d)

12. Determine the transfer function for the practical differentiator

a) Vo(s) /V1(s) = -S×RF×C1/(1+R1×C1)2
b) Vo(s) /V1(s) = -S×RF×C1/(1+RF×C1)2
c) Vo(s) /V1(s) = -S×RF×C1/(1+R1×CF)2
d) None of the mentioned